The figure above represents an antenna tower with two guy wires that extend from point Q, 40 feet above the ground, to points P and R as shown. If the two wires have equal length, approximately what is the total length, in feet, of the two wires? – OGQR 2020 Question #97 with Solution

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OGQR 2020: Question No. 97

The figure above represents an antenna tower with two guy wires that extend from point Q, 40 feet above the ground, to points P and R as shown. If the two wires have equal length, approximately what is the total length, in feet, of the two wires?

Source OGQR 2020
Type Problem Solving
Topic Geometry
Sub-Topic Triangles
Difficulty Medium

Solution

Given

In this question, we are given

  • The given figure represents an antenna tower with two guy wires that extend from point Q, 40 feet above the ground, to points P and R as shown.
  • The two wires have equal length.

To Find

We need to determine

  • The total approximate length, in feet, of the two wires.

Approach & Working

As the lengths of two wires are same, PQ = QR.

Hence, PQR is an isosceles triangle.

  • In an isosceles triangle, perpendicular from the top vertex to the base bisects the base.
  • Therefore, each of the two right-angled triangles has a base of 30 feet.

Hence, we can say

  • QR2 = 302 + 402 = 502

Or, QR = 50

Thus, the length of the two wires combined = (50 + 50) feet = 100 feet

Hence, the correct answer is option C.

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