{"id":57463,"date":"2025-08-22T13:40:17","date_gmt":"2025-08-22T08:10:17","guid":{"rendered":"https:\/\/e-gmat.com\/blogs\/?p=57463"},"modified":"2025-09-05T00:51:53","modified_gmt":"2025-09-04T19:21:53","slug":"how-many-positive-three-digit-integers-are-divisible-by-both","status":"publish","type":"post","link":"https:\/\/e-gmat.com\/blogs\/how-many-positive-three-digit-integers-are-divisible-by-both\/","title":{"rendered":"How many positive three-digit integers are divisible by both 3 and 4?"},"content":{"rendered":"<span class=\"rt-reading-time\" style=\"display: block;\"><span class=\"rt-label rt-prefix\">A <\/span> <span class=\"rt-time\">3<\/span> <span class=\"rt-label rt-postfix\">min read <\/span><\/span>\n<p>How many positive three-digit integers are divisible by both&nbsp;3&nbsp;and&nbsp;4?<\/p>\n\n\n\n<p>A. 75<\/p>\n\n\n\n<p>B. 128<\/p>\n\n\n\n<p>C. 150<\/p>\n\n\n\n<p>D. 225<\/p>\n\n\n\n<p>E. 300<\/p>\n\n\n\n<h2>Solution:<\/h2>\n\n\n\n<ol type=\"1\"><li><strong>Translate the problem requirements<\/strong>: We need to find three-digit numbers (100 to 999) that are divisible by both 3 and 4, which means finding numbers divisible by their LCM = 12<\/li><li><strong>Identify the range boundaries for multiples of 12<\/strong>: Find the smallest and largest three-digit multiples of 12 to establish our counting range<\/li><li><strong>Count the multiples using division<\/strong>: Use the range of multiples to calculate how many multiples of 12 exist in the three-digit range<\/li><\/ol>\n\n\n\n<h3 id=\"h-execution-of-strategic-approach\">Execution of Strategic Approach<\/h3>\n\n\n\n<h4 id=\"h-1-translate-the-problem-requirements\">1. Translate the problem requirements<\/h4>\n\n\n\n<p>Let&#8217;s start by understanding what we&#8217;re looking for in everyday terms. We need three-digit numbers that are divisible by both 3 and 4.<\/p>\n\n\n\n<p>Three-digit numbers are simply the numbers from 100 to 999 &#8211; these are all the numbers that have exactly three digits.<\/p>\n\n\n\n<p>Now, when a number is divisible by both 3 and 4, it means the number can be divided evenly by both of these numbers with no remainder. For example, let&#8217;s check 12:&nbsp;12 <em>divided by<\/em> 3 = 4&nbsp;(no remainder) and&nbsp;12 <em>divided by<\/em> 4 = 3&nbsp;(no remainder).<\/p>\n\n\n\n<p>Here&#8217;s the key insight: when we want a number divisible by both 3 and 4, we&#8217;re really looking for numbers divisible by their Least Common Multiple (LCM). Since 3 and 4 share no common factors (3 is prime and doesn&#8217;t divide 4), their LCM is simply&nbsp;3 <em>multiplied by <\/em>4 = 12.<\/p>\n\n\n\n<p>So our problem becomes:&nbsp;<strong>How many three-digit numbers are divisible by 12?<\/strong><\/p>\n\n\n\n<p><em>Process Skill: TRANSLATE &#8211; Converting the &#8220;divisible by both&#8221; requirement into &#8220;divisible by LCM&#8221;<\/em><\/p>\n\n\n\n<h4 id=\"h-2-identify-the-range-boundaries-for-multiples-of-12\">2. Identify the range boundaries for multiples of 12<\/h4>\n\n\n\n<p>Now we need to find the smallest and largest three-digit numbers that are multiples of 12.<\/p>\n\n\n\n<p><strong>Finding the smallest three-digit multiple of 12:<\/strong><\/p>\n\n\n\n<p>The smallest three-digit number is 100. Let&#8217;s see:&nbsp;100 <em>divided by<\/em> 12 = 8.33&#8230;.&nbsp;This means 100 is between the 8th and 9th multiples of 12. Since we need the next whole multiple, we want the 9th multiple:&nbsp;12 <em>multiplied by<\/em> 9 = 108.<\/p>\n\n\n\n<p>Let&#8217;s verify:&nbsp;&nbsp;108 <em>divided by<\/em> 3 = 36 \u2713 and&nbsp;&nbsp;108 <em>divided by<\/em> 4 = 27 \u2713<\/p>\n\n\n\n<p><strong>Finding the largest three-digit multiple of 12:<\/strong><\/p>\n\n\n\n<p>The largest three-digit number is 999. Let&#8217;s see:&nbsp;999 <em>divided by<\/em> 12 = 83.25. This means 999 is between the 83rd and 84th multiples of 12. Since we need a whole multiple, we want the 83rd multiple:&nbsp;12 <em>multiplied by<\/em> 83 = 996.<\/p>\n\n\n\n<p>Let&#8217;s verify:&nbsp;&nbsp;996 <em>divided by<\/em> 3 = 332 \u2713 and&nbsp;&nbsp;996 <em>divided by<\/em> 4 = 249 \u2713<\/p>\n\n\n\n<p>So our three-digit multiples of 12 range from the 9th multiple (108) to the 83rd multiple (996).<\/p>\n\n\n\n<h4 id=\"h-3-count-the-multiples-using-division\">3. Count the multiples using division<\/h4>\n\n\n\n<p>Now we need to count how many multiples of 12 exist from the 9th multiple to the 83rd multiple, inclusive.<\/p>\n\n\n\n<p>This is like counting from 9 to 83. When we count consecutive integers from a starting number to an ending number, the formula is:<\/p>\n\n\n\n<p><strong>Count = Last number &#8211; First number + 1<\/strong><\/p>\n\n\n\n<p>In our case:<\/p>\n\n\n\n<p>Count =&nbsp;83 &#8211; 9 + 1 = 75<\/p>\n\n\n\n<p>Let&#8217;s double-check this makes sense: if we had multiples from the 9th to the 11th, that would be 3 multiples (9th, 10th, 11th), and indeed&nbsp;&nbsp;11 &#8211; 9 + 1 = 3 \u2713<\/p>\n\n\n\n<h4 id=\"h-4-final-answer\">4. Final Answer<\/h4>\n\n\n\n<p>There are&nbsp;<strong>75<\/strong>&nbsp;positive three-digit integers that are divisible by both 3 and 4.<\/p>\n\n\n\n<p>This matches answer choice&nbsp;<strong>A. 75<\/strong><\/p>\n\n\n\n<p><strong>Quick verification:<\/strong>&nbsp;Our range includes multiples from 108 (12 <em>multiplied by<\/em> 9) to 996 (12 <em>multiplied by<\/em> 83), giving us 83 &#8211; 9 + 1 = 75&nbsp;numbers total.<\/p>\n\n\n\n<h3 id=\"h-common-faltering-points\">Common Faltering Points<\/h3>\n\n\n\n<h4 id=\"h-errors-while-devising-the-approach\">Errors while devising the approach<\/h4>\n\n\n\n<ul><li><strong>Misunderstanding &#8220;divisible by both&#8221;:<\/strong>&nbsp;Students may try to count numbers divisible by 3 and numbers divisible by 4 separately, then add them together. This double-counts numbers and ignores that we need numbers divisible by BOTH conditions simultaneously. The correct approach requires finding the LCM (12) first.<\/li><li><strong>Forgetting the three-digit constraint:<\/strong>&nbsp;Students may calculate all multiples of 12 without restricting to the range 100-999, leading to an incorrect count that includes one-digit, two-digit, or four-digit numbers.<\/li><li><strong>Attempting to list all numbers individually:<\/strong>&nbsp;Instead of using the systematic LCM approach, students may try to manually check each three-digit number for divisibility by both 3 and 4, which is time-consuming and error-prone on the GMAT.<\/li><\/ul>\n\n\n\n<h4 id=\"h-errors-while-executing-the-approach\">Errors while executing the approach<\/h4>\n\n\n\n<ul><li><strong>Incorrect boundary identification:<\/strong>&nbsp;When finding&nbsp;100 <em>divided by<\/em> 12 = 8.33, students may incorrectly use the 8th multiple (96) instead of rounding up to the 9th multiple (108). Similarly, for&nbsp;999 <em>divided by<\/em> 12 = 83.25, they may round up to the 84th multiple instead of down to the 83rd multiple.<\/li><li><strong>Arithmetic errors in multiplication:<\/strong>&nbsp;Students may make calculation mistakes when computing&nbsp;12 <em>multiplied by<\/em> 9 = 108&nbsp;or&nbsp;12 <em>multiplied by<\/em> 83 = 996, leading to wrong boundary values and ultimately an incorrect count.<\/li><li><strong>Forgetting the &#8220;+1&#8221; in counting:<\/strong>&nbsp;When counting from the 9th to 83rd multiple, students often forget that counting consecutive integers requires the formula (last &#8211; first + 1), calculating&nbsp;83 &#8211; 9 = 74&nbsp;instead of&nbsp;83 &#8211; 9 + 1 = 75.<\/li><\/ul>\n\n\n\n<h4 id=\"h-errors-while-selecting-the-answer\">Errors while selecting the answer<\/h4>\n\n\n\n<p>No likely faltering points &#8211; the calculation directly yields 75, which clearly matches answer choice A.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>How many positive three-digit integers are divisible by both&nbsp;3&nbsp;and&nbsp;4? A. 75 B. 128 C. 150 D. 225 E. 300 Solution: Translate the problem requirements: We need to find three-digit numbers (100 to 999) that are divisible by both 3 and 4, which means finding numbers divisible by their LCM = 12 Identify the range boundaries [&hellip;]<\/p>\n","protected":false},"author":102457,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"off","_et_pb_old_content":"","_et_gb_content_width":"","ub_ctt_via":""},"categories":[94,100],"tags":[],"featured_image_src":null,"author_info":{"display_name":"Kashish Garg","author_link":"https:\/\/e-gmat.com\/blogs\/author\/kashish\/"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.1.1 (Yoast SEO v17.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>How many positive three-digit integers are divisible by both 3 and 4?<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/neuron.e-gmat.com\/quant\/questions\/how-many-positive-three-digit-integers-are-divisible-by-both-1003.html\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How many positive three-digit integers are divisible by both 3 and 4?\" \/>\n<meta property=\"og:description\" content=\"How many positive three-digit integers are divisible by both&nbsp;3&nbsp;and&nbsp;4? 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