{"id":21349,"date":"2019-05-21T01:54:07","date_gmt":"2019-05-20T20:24:07","guid":{"rendered":"https:\/\/e-gmat.com\/blogs\/?p=21349"},"modified":"2022-11-17T11:38:29","modified_gmt":"2022-11-17T06:08:29","slug":"in-the-figure-above-the-area-of-the-parallelogram-is-ogqr-2020-question-85-with-solution","status":"publish","type":"post","link":"https:\/\/e-gmat.com\/blogs\/in-the-figure-above-the-area-of-the-parallelogram-is-ogqr-2020-question-85-with-solution\/","title":{"rendered":"In the figure above, the area of the parallelogram is &#8211; OGQR 2020 Question #85 with Solution"},"content":{"rendered":"<span class=\"rt-reading-time\" style=\"display: block;\"><span class=\"rt-label rt-prefix\">A <\/span> <span class=\"rt-time\">2<\/span> <span class=\"rt-label rt-postfix\">min read <\/span><\/span><h2>OGQR 2020: Question No. 85<\/h2>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-21352 aligncenter\" src=\"https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85-300x136.png\" alt=\"\" width=\"300\" height=\"136\" srcset=\"https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85-300x136.png 300w, https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85.png 304w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>In the figure above, the area of the parallelogram is<\/p>\n<table>\n<tbody>\n<tr>\n<td width=\"301\">Source<\/td>\n<td width=\"301\">OGQR 2020<\/td>\n<\/tr>\n<tr>\n<td width=\"301\">Type<\/td>\n<td width=\"301\">Problem Solving<\/td>\n<\/tr>\n<tr>\n<td width=\"301\">Topic<\/td>\n<td width=\"301\">Geometry<\/td>\n<\/tr>\n<tr>\n<td width=\"301\">Sub-Topic<\/td>\n<td width=\"301\">Quadrilateral<\/td>\n<\/tr>\n<tr>\n<td width=\"301\">Difficulty<\/td>\n<td width=\"301\">Medium<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h3>Solution<\/h3>\n<h4><strong><u>Given<\/u><\/strong><\/h4>\n<p>In this question, we are given<\/p>\n<ul>\n<li>The diagram of a parallelogram, where the adjacent sides are of length 8 and 12<\/li>\n<li>One angle between the sides is 60\u00b0<\/li>\n<\/ul>\n<h4><strong><u>To Find<\/u><\/strong><\/h4>\n<p>We need to determine<\/p>\n<ul>\n<li>The area of the parallelogram<\/li>\n<\/ul>\n<h4><strong><u>Approach &amp; Working<\/u><\/strong><\/h4>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-21353 aligncenter\" src=\"https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85.2-300x142.png\" alt=\"\" width=\"300\" height=\"142\" srcset=\"https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85.2-300x142.png 300w, https:\/\/e-gmat.com\/blogs\/wp-content\/uploads\/2019\/05\/85.2.png 304w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Let us assume the parallelogram is PQRS, and QT is the perpendicular dropped from point Q to the side PS.<\/p>\n<ul>\n<li>Hence, we can say that PQT is a 30\u00b0-60\u00b0-90\u00b0 triangle, and the side ratio is 1: \u221a3: 2.<\/li>\n<li>QT: PQ = \u221a3: 2<\/li>\n<\/ul>\n<p>Or, QT = \u221a3\/ 2&nbsp;* PQ = \u221a3\/ 2&nbsp;* 8 = 4\u221a3<\/p>\n<ul>\n<li>Therefore, the area of the quadrilateral = PS * QT = 12 * 4\u221a3 = 48\u221a3 (PS = QR)<\/li>\n<\/ul>\n<p>Hence, the correct answer is option D.<\/p>\n<blockquote><p>Did you know a 700+ GMAT Score can increase your chances to get into your dream business school? We can help you achieve that. Why don\u2019t you<a href=\"https:\/\/e-gmat.com\/ft-gmat\/?channel=blogsin_article&amp;utm_source=blogs&amp;utm_medium=in_article&amp;utm_campaign=free_trial&amp;utm_term=blogs_in_article_lekhika\" target=\"_blank\" rel=\"noopener noreferrer external\" data-wpel-link=\"external\">&nbsp;<strong>try out our FREE Trial?<\/strong><\/a><strong>&nbsp;<\/strong>We are the<strong>&nbsp;<a href=\"https:\/\/gmatclub.com\/reviews\/e-gmat-6\" target=\"_blank\" rel=\"noopener noreferrer external\" data-wpel-link=\"external\">most reviewed online GMAT Preparation company in GMATClub<\/a><\/strong>&nbsp;with more than 1950 reviews as of October 2020.<\/p><\/blockquote>\n\n<div class=\"ub-buttons align-button-center\"  id=\"ub-button-61168913-d766-4a48-91d4-c0b045938593\"><div class=\"ub-button-container\">\n    <a href=\"https:\/\/resources.e-gmat.com\/sign-up-free-trial\" target=\"_blank\" rel=\"noopener noreferrer external\" class=\"ub-button-block-main ub-button-medium ub-button-flex-medium\" role=\"button\" data-wpel-link=\"external\">\n    <div class=\"ub-button-content-holder\"><span class=\"ub-button-block-btn\">Sign up for a Free Trial<\/span>\n    <\/div><\/a><\/div><\/div>","protected":false},"excerpt":{"rendered":"<p>OGQR 2020: Question No. 85 In the figure above, the area of the parallelogram is Source OGQR 2020 Type Problem Solving Topic Geometry Sub-Topic Quadrilateral Difficulty Medium Solution Given In this question, we are given The diagram of a parallelogram, where the adjacent sides are of length 8 and 12 One angle between the sides [&hellip;]<\/p>\n","protected":false},"author":102413,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_et_pb_use_builder":"","_et_pb_old_content":"","_et_gb_content_width":"","ub_ctt_via":""},"categories":[104,44,94,60,100],"tags":[],"featured_image_src":null,"author_info":{"display_name":"Ashutosh","author_link":"https:\/\/e-gmat.com\/blogs\/author\/ashutoshe-gmat-com\/"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.1.1 (Yoast SEO v17.1) - 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